Hi, As question explained here
http://stackoverflow.com/questions/6493727/can-i-assign-items-in-an-array-all-at-once-in-delphi-pascal and the easiest answer is :

type

  TIntArray =arrayof integer;procedure TForm1.Button1Click(Sender:
  TObject);var MyArr: TIntArray;begin MyArr :=
  TIntArray.Create(10,20,30,40);end;

But problems are : Lazarus doesnt recognize Create for array but FPC will compile it but it seems it doesnt work so I want to ask what should I do for?assign items in an array all at once in FreePascal?

Regards, Ara

The above is the only correct solution.

If the Lazarus codetools do not recognize this, then a bug report should be created for the IDE codetools.

Michael.

Michael can I ask why we cant do something like this :

?MyArr :=[10, 20, 30, 40]; ??

Regards, Ara

Aradeonas wrote

Michael can I ask why we cant do something like this : > ?MyArr :=[10, 20, 30, 40]; ??

Because of 2 reasons:

1. Delphi introduced the create constructor.

2. A literal such as [10,20,30,40] is a set in pascal, not an array.

Michael.

The answer is no longer correct with current Delphi versions. It now is "because we haven't implemented it yet".

Regards,
Sven
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Hmm, really:?http://blog.marcocantu.com/blog/2014_september_dynamic_arrays_delphixe7.html ?
V.

I like this one more :

It now is "because we haven't implemented it yet"

Because :

A literal such as [10,20,30,40] is a set in pascal, not an array.

Is not a good one I think. For example this one works :

function Test(Arr:array of integer); Usage: Test([1,2,3]);

Why it cant work for assigning a var but it can be used for parameters?

Regards, Ara

Indeed. Well, I'm still on XE, the jump to XE 10 is for next month. Seems I'll have some reading up to do...

Disregarding the fact that they introduced now 2 syntaxes to initialize an array, I'm curious what Jonas is going to say, because I remember he always advocates that the type of an expression is determined by the terms/factors in the expression, not by what you assign it to.

For
['abc','def'] + ['ghi','jkl']
it is more or less clear.

But what is the type of this expression:
[1,2,3] + [4,5,6]
is it an array or a set ?

It probably means that they regard [] always as an array, and added some kind of automatic set-to-array type assignment compatiblity for types that somehow fit in a set.

Michael.

always advocates that the type of an expression is determined by the terms/factors in the expression, not by what you assign it to.

that somehow fit in a set.

Well... FPC is handling them special as well, after all we support open array parameters as well which clearly are no sets either. ;) They are parsed into an array constructor nodes and then converted into either an open array or a set by the node they're contained in. Support for normal arrays will simply(TM) mean the addition of additional special cases... (yes, it's easier said than done ;) )

Regards,
Sven
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