Hi,
First of all, I did some research and found this:
But that did not convince me. So here is my situation and question.
I have the following case:
TBase = class
public
constructor Create; //VER-0
end;
TDerived = class(TBase)
private
constructor Create(param1); //VER-1
public
constructor Create; reintroduce; //VER-0'
constructor Create(param1, param2); //VER-2
constructor Create(param1, param2, param3); //VER-3
end;My purpose is that while using TDerived, only VER-2 and VER-3 of the constructors should be used, VER-0 and VER-1 are used INTERNALLY by VER-2 and VER-3 and should NOT be used publicly.
As restricted by the "rule of OOP", you cannot make a method which is public in base class private in descendants, I plan to do the following:
1) reintroduce a Create (without param), which just throw an exception explaining that this MUST NOT be called directly. Meanwhile, use "inherited Create" internally in other versions of the constructors.
2) Make VER-1 private so that it cannot be called outside.
Now the compiler throw a warning that constructor should be public.
In the post I referred, Graeme explained that:
============================================================== Your code is flawed. Object Pascal is quite clear regarding visibility rules. TObject has a Public constructor. You can only raise the visibility from there, not reduce visibility.
Imagine how confusing it will be if you code was a library of some sorts and other developers had to use it. In a inherited class, you have public visibility to the constructor or some other method, and then suddenly in the descendant class the methods are hidden from the developer?? Not a good idea. ==============================================================
I don't understand this, because to me, the VER-1 constructor is introduced in TDerived, make it non-public does NOT reduce the visibility of VER-0 constructor, hence is not a violation of visibility rules, is it???
Thanks!
Xiangrong
