Hello all,

In the old TP there just to be a way to read a string from the command line at the same time you invoked the program thus doing:

myprogram param1 param2

made those two variables available to the program and you could do some action, just like passing variables to a function.

How do you do that in FPC in Linux?

Thanks
-pa

Hi Paul!

How do you do that in FPC in Linux?

You can use something like this:

program argtest;
var i: integer;
begin
   for i := 0 to argc do
   begin
      writeln (argv[i]);
   end;
end.

Ciao,

Olaf

Hi again!

Sorry, it has to be:

   for i := 0 to argc-1 do

argc is the number of arguments, argv is a string-vector. I think it is an array of c-strings, isn't it?

Ciao,

Olaf

Don't know if it's different in Linux, but in the DOS version at least you can use paramstr(1), paramstr(2), etc.

if (paramstr(1)='test') then writenln('you passed the parameter passing test')

regards,
DONALD.

E-mail -
BIG DON's Home-page - http://jedi.apana.org.au/~jims_son Pedder Passer Rating - http://jedi.apana.org.au/~jims_son/PPR AusNFL mailing-list - http://jedi.apana.org.au/mailman/listinfo/ausnfl

"What I always wanted is to be accepted, not understood" - MAN RAY

It isn't any different on Linux:

paramCount (returns the number of parameters passed to the program) paramStr(i) (returns the i'th parameter)

cheers
James

There is a subtle difference between ParamStr(0) and argv[0]:

argv[0] is the verbatim command passed to the shell. ParamStr(0) is the full path to the executable.

Neither of these will dereference a symlink, to do that you can call ReadLink recursively, or ReadLink(/proc/<PID>/exe)

Also note that the argv's are zero-based pchar's,
the paramstr's are one-based pascal strings.

The argv's are also writeable:

 This works:
   argv[0][1]:='x';
 But this doesn't:
   ParamStr(0)[1]:='x';

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